Дано:
у=x²sinx
x₀=π/2
y'=x(2*sin(x)+x*cos(x))
у'(x₀)=y'(π/2)=π/2(2*sin(π/2)+π/2*cos(π/2))=π/2(2*1+π/2*0)=π/2*2=π
Дано:
у=x²sinx
x₀=π/2
y'=x(2*sin(x)+x*cos(x))
у'(x₀)=y'(π/2)=π/2(2*sin(π/2)+π/2*cos(π/2))=π/2(2*1+π/2*0)=π/2*2=π