ROH+HBr=RBr+H2O
n(RBr)=n(H2O)=12.6/18=0.7
Mr(RBr)=14n+81
86.1=(14n+81)*0.7
9.8n=29.4
n=3
R=C3H7
ответ=C3H7OH
ROH+HBr=RBr+H2O
n(RBr)=n(H2O)=12.6/18=0.7
Mr(RBr)=14n+81
86.1=(14n+81)*0.7
9.8n=29.4
n=3
R=C3H7
ответ=C3H7OH