(x-x1)/(x2-x1)=(y-y1)(y2-y1)
(x-(-5))/(3-(-5))=(y-32)/(-8-32)
(x+5)/8=(y-32)/(-40)
-40(x+5)=8(y-32)
-40x-200=8y-256
-40x-8y+56=0
5x+y-7=0 или y=-5x-7
(x-x1)/(x2-x1)=(y-y1)(y2-y1)
(x-(-5))/(3-(-5))=(y-32)/(-8-32)
(x+5)/8=(y-32)/(-40)
-40(x+5)=8(y-32)
-40x-200=8y-256
-40x-8y+56=0
5x+y-7=0 или y=-5x-7