Calculate the amount of substance which corresponds to 49 g of copper hydroxide (II).

given:
m(Сu(ОН)2) = 49 g
find:
ν(Сu(ОН)2)  - ?
Solution:
ν= m/( М).
М(Сu(ОН)2) = 64  + 16 • 2 + 1 • 2  = 98 g/mol
ν(Сu(ОН)₂)= (m(Сu(ОН)₂))/(М(Сu(ОН)₂))= (49 g)/(98 g/mol)=0,5 mol
Answer:ν(Сu(ОН)2) =0,5 mol.