Al(OH)3+3NaOH=Na3[Al(OH)6]]
n(Al(OH)3)=3.9/78=0.05моль
m(NaOH)=0.15*40=6г
m(раствора NaOH)=6*100/20=30г
М(NaOH)=30*1.2=36г
2Al(OH)3+3H2SO4=Al2(SO4)3+6H2O
m(H2SO4)=0.075*98=7.35г
m(р-ра H2SO4)=7.35*100/16=46г
V(H2SO4)=1.1*46=50.5г
Al(OH)3+3NaOH=Na3[Al(OH)6]]
n(Al(OH)3)=3.9/78=0.05моль
m(NaOH)=0.15*40=6г
m(раствора NaOH)=6*100/20=30г
М(NaOH)=30*1.2=36г
2Al(OH)3+3H2SO4=Al2(SO4)3+6H2O
m(H2SO4)=0.075*98=7.35г
m(р-ра H2SO4)=7.35*100/16=46г
V(H2SO4)=1.1*46=50.5г