X(x^2+2x+1)=2(x+1) решите уравнение

X (x^2 + 2x + 1) = 2(x + 1)
x (x + 1)^2 - 2(x + 1) = 0
(x + 1) (x (x + 1) - 2) = 0

1) x + 1 = 0
x1 = - 1

2) x (x + 1) - 2 = 0
x^2 + x - 2 =  0
D = 1 +  8 = 9
x2 = ( - 1 + 3)/2 = 2/2 = 1;
x3 = ( - 1 - 3)/2 = - 4/2 = - 2

ответ
- 2;  - 1; 1