The combustion of pentane proceeds according to equation C;H12 + 80, - SCO, + 6H,O. The enthalpy change of this process is -3509.2 kJ/mol. Use the following from Hess's law and calculate the enthalpy of formation of 1 mol of pentane, if AH, (CO.) = -393.5 kl/mol, AH, (H,O) = -241.8 kJ/mol, AH (0,) - 0​

катя19052    1   09.02.2021 12:59    0