Sqrt(3)*sinx - cosx = 2cos5x , нужно .

2(√3/2sinx-1/2cosx)-2cos5x=0
sin(x-π/6)-sin(π/2-5x)=0
-2sin(2x+π/12)cos(3x-π/12)=0
sin(2x+π/12)=0⇒2x+π/12=πn⇒2x=-π/12+πn⇒x=-π/24+πn/2
cos(3x-π/12)=0⇒3x-π/12=π/2+πn⇒3x=7π/6+πn⇒x=7π/18+πn/3