(x-3)²/x²+2x-15
x²+2x+15 = 0
Теорема Виета:
{x1+x2 = -2
{x1•x2 = 15
x1 = -5
x2 = 3
x²+2x+15 = (x+5)(x-3)
(x-3)²/(x+5)(x-3) = x-3/x+5
(x-3)²/x²+2x-15
x²+2x+15 = 0
Теорема Виета:
{x1+x2 = -2
{x1•x2 = 15
x1 = -5
x2 = 3
x²+2x+15 = (x+5)(x-3)
(x-3)²/(x+5)(x-3) = x-3/x+5