Объяснение:
1) 4t³ + t² = 0
t²(4t+1) = 0
t² = 0 ⇒ t = 0
4t+1 = 0 ⇒ t = -1/4
2) 2а² – 5а = 0
a(2a-5) = 0
a = 0
2a-5 = 0
2a = 5 ⇒ a = 2.5
3) (х – 7) + х(х – 7) = 0
(х – 7)(1 + х) = 0
x -7 = 0 ⇒ x = 7
x+1 = 0 ⇒ x = -1
Объяснение:
1) 4t³ + t² = 0
t²(4t+1) = 0
t² = 0 ⇒ t = 0
4t+1 = 0 ⇒ t = -1/4
2) 2а² – 5а = 0
a(2a-5) = 0
a = 0
2a-5 = 0
2a = 5 ⇒ a = 2.5
3) (х – 7) + х(х – 7) = 0
(х – 7)(1 + х) = 0
x -7 = 0 ⇒ x = 7
x+1 = 0 ⇒ x = -1