Решите уравнения а)х²+16х-51=0 б)2х²-13х+6=0

X² + 16x - 51 = 0
D = b² - 4ac = 16² - 4*(- 51) = 256 + 204 = 460
x1,2 = ( - 16 +/-√460) / 2

2x² - 13x + 6 = 0
D = b² - 4ac = (-13)² - 4*2*6 = 169 - 48 = 121 = 11²
x1 = ( 13 + 11) / 4 = 6
x2 = ( 13 - 11) / 4 = 0,5