Решите уравнение: x/x-1 + x+1/ x+3 = 1/x^2+2x-3 ) заранее )

x/x-1 + x+1/ x+3 = 1/x^2+2x-3

x(x+3)+(x+1)(x-1)/(x-1)(x+3) = 1/x^2+2x-3

x^2+3x+x^2-x+x-1/(x-1)(x+3) = 1/x^2+2x-3

x^2+3x+x^2-x+x-1/(x-1)(x+3) = 1/x^2+2x-3

2x^2+3x-1/(x-1)(x+3) = 1/x^2+2x-3

2x^2+3x-1/ x^2+2x-3- 1/x^2+2x-3=0

2x^2+3x-1-1/x^2+2x-3=0

2x^2+3x-2/x^2+2x-3=0

2x^2+3x-2=0

d=9+16=25=5^2

x1=-3+5/4=2/4=1/2

x2=-3-5/4=-8/4=-2