Решите уравнение: (x-5)^2=1 (3х+6)^2=100 (3-2x)^2=25

(X-5)^2=1
X^2-10x+25=1
X^2-10x+24=0
D=100-96=4
X1=10+2/2=6
X2=10-2/2=4

(3x+6)^2=100
9x^2+36x+36-100=0
9x^2+36x-64=0
D=1296-(-2304)=3600
X1=-36+60/18=24/18=8/6=1 1/3
X2=-36-60/18=-96/18=-32/6=-5 1/3

(3-2x)^2=25
9-12x+4x^2=25
4x^2-12x+9-25=0
4x^2-12x-16=0|:4
X^2-3x-4=0
D=9+16=25
X1=3+5/2=4
X2=3-5/2=-1