Решите уравнение f`(x)=0 а)f(x)=3x^2+8x+2 в)f(x)=3/2x^2+4x-1

A) f(x) = 3x² + 8x + 2
f '(x) = (3x²)' + (8x)' + 2' = 6x + 8
6x + 8 = 0
6x = - 8
x = - 1 1/3
б) f(x) = 3/2x² + 4x - 1
f '(x) = (3/2x²)' + (4x)' -1' = 3x + 4
3x + 4 = 0
3x = - 4
x = - 1 1/3