)решите неравенство: (9-x^2)/(3x+1) =2/x

Question

Алгебра: )решите неравенство: (9-x^2)/(3x+1) =2/x

texin508 · Answer

(9-x^2)/(3x+1) =2/x ODZ 3x+1=0 3x=-1 x=-1/3(ne mojet but ) x=0(ne mojet but ) (x(9-x^2))/(3x+1)-(2*(9-x^2))/x =0 9x-x^3-6x+2 =0 x^3-3x+2 =0 x^3-3x+2=0 ((x-1)^2)*(x+2) (x-1)^2=0 D=0 x=1; x+2=0 x=-2 (-beskone4nostu;-2]U(-1/3;+beskone4nostu)  ...

)решите неравенство: (9-x^2)/(3x+1)> =2/x

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