Решите 2x³-∛x +3√x dx 5x² неопределеный интеграл

∫ (2X³-∛X +3√X ) / 5x²  = ∫ 2X³/5x² dx -∫ ∛X/5x² dx +∫ 3√X/5x² dx =
= 2/5 ∫ X³/x² dx  - 1/5 ∫ ∛X/x² dx + 3/5 ∫√X/x² dx =
=2/5 ∫ X dx  - 1/5 ∫ ∛X/x² dx + 3/5 ∫√X/x² dx =
= 1/5 x^2 + 3/10 ∛x/x - 6/5 *1/√x =
= x^2/5 + 3∛x/10x - 6/5√x