Решите 2^(x-1)-3^x=3^(x-1)-2^(x+2)

2^(x-1)-3^x=3^(x-1)-2^(x+2)
2^(x-1)+2^(x+2)=3^(x-1)+3^x
2^(x-1)*(1+2³)=3^(x-1)*(1+3)
9*2^(x-1)=4*3^(x-1) | : 4*3^(x-1)
[9*2^(x-1)]/ [4*3^(x-1)]=1
2^(x-3)/3^(x-3)=1
(2/3)^(x-3)=1
(2/3)^(x-3)=(2/3)⁰
x-3=0, x=3