Решить уравнение 39+(4х+3)^2=2+4(2х+1)^2

39+(4х+3)^2=2+4(2х+1)^2
39 + 16x^2 + 24x + 9 = 2 + 4(4x^2 + 4x + 1)
48 + 16x^2 + 24x = 2 + 16x^2 + 8x + 2
48 - 2 - 2 = 16x^2 - 16x^2 + 8x - 24x
44 = -16x
11 = -4x
x = -11/4
x = 2 3/4