Решить уравнение: 3-4sin^2(3x+п/3)=0

3 - 4sin²(3x + π/3) = 0
3 = 4sin²(3x + π/3)
sin²(3x + π/3) = 3/4
sin(3x + π/3) = ±√3/2
1) sin(3x + π/3) = √3/2
3x + π/3 = (-1)ⁿπ/3 + πn, n ∈ Z
x = (-1)ⁿπ/9 - π/9 + πn/3, n ∈ Z
2) sin(3x + π/3) = -√3/2
3x + π/3 = (-1)ⁿ+¹π/3 + πn, n ∈ Z
x = (-1)ⁿ+¹π/9 - π/9 + πn/3, n ∈ Z