решить х/4+у/5+z/6+z/4+у/5+х/6. с подробным решением, .

Y/5 +y/5 =2y/5

x/4. +x/6 =(3x+2x)/12 =5x/12

z/6 +z/4 =(2z+3z)/12 =5z/12

2y/5 +5x/12 +5z/12 =2y/5 +(5x+5z)/12 =

=(2y*12 +5(5x+5z))/60 =(24y+25x+25z)/60

(24y/60) +(25x+25z)/60 =221/60

(2y/12)=(221 -(25x+25z))/60

2y=12(221-(25x+25z))/60

2y=(221-(25x+25z))/60

y=(221-(25x+25y))/120