Решить (х-1)в квадрате - 4(х+1)в квадрате - 6(х+1)(х-1)

Выражение: (x-1)^2-4*(x+1)^2-6*(x+1)*(x-1)
ответ: -9*x^2-10*x+3
1. x^2-2*x+1-4*(x+1)^2-6*(x+1)*(x-1)
2. x^2-2*x+1-4*(x^2+2*x+1)-6*(x+1)*(x-1)
3. x^2-2*x+1-(4*x^2+8*x+4)-6*(x+1)*(x-1)
4. x^2-2*x+1-4*x^2-8*x-4-6*(x+1)*(x-1)
5. -3*x^2-2*x+1-8*x-4-6*(x+1)*(x-1)
6. -3*x^2-10*x+1-4-6*(x+1)*(x-1)
7. -3*x^2-10*x-3-6*(x+1)*(x-1)
8. -3*x^2-10*x-3-(6*x+6)*(x-1)
9. -3*x^2-10*x-3-(6*x^2-6)
10. -3*x^2-10*x-3-6*x^2+6
11. -9*x^2-10*x-3+6
12. -9*x^2-10*x+3