Решить: (4√3-3√2)в квадрате+√54(8-7√6).

=48 - 24√6 + 18 + 8*3√6 - 7√324 = 48 + 18 -24√6 + 24√6 - 7*18 = 66 - 126 = -60

1) ( 4V 3 - 3V 2)^2 = ( V 48 - V 18 )^2 = ( V48)^2 - 2 * V 48 * V 18 + ( V 18)^2 =
= 48 + 18 - 2 V 864 = 66 - 2 V 864 = 66 - 2 V ( 4 * 4 * 9 * 6) = 66 - ( 2 * 2 * 2 * 3) V 6 =
= 66 - 24 V 6 

2) V 54 * ( 8 - 7V6 ) = 8 V 54 - 7 V ( 54*6) = 8 V 54 - 7 V 324 = 8 V ( 6*9) - 7 * 18 = 
= 24 V 6 - 126 

3) 66 - 24 V 6 + 24 V 6 - 126 = 66 - 126 = ( - 60 )

ответ ( - 60 )