x² – 12x + 20 = (x – 2)(x – 10)
Объяснение:
x² – 12x + 20 = 0
D = 12² – 4·20 = 64 = 8²
x₁ = (12 – 8) / 2 = 2
x₂ = (12 + 8) / 2 = 10
х²-12х+20= (х²- 2•х•6 +6²)+20 -6²=
= (х- 6)²+20-36= (х-6)² -16= (х-6)²- 4²=
(х-6+4)(х-6-4)=(х-2)(х-10)
Или:
х²-12х+20=0
D= b²- 4ac= 144-80=64 D>0,два корня.
х1,х2= - b ± √D/2a= 12± 8/2= 2 ; 10
x²-12x+20= (x -2)(x-10)
x² – 12x + 20 = (x – 2)(x – 10)
Объяснение:
x² – 12x + 20 = 0
D = 12² – 4·20 = 64 = 8²
x₁ = (12 – 8) / 2 = 2
x₂ = (12 + 8) / 2 = 10
x² – 12x + 20 = (x – 2)(x – 10)
х²-12х+20= (х²- 2•х•6 +6²)+20 -6²=
= (х- 6)²+20-36= (х-6)² -16= (х-6)²- 4²=
(х-6+4)(х-6-4)=(х-2)(х-10)
Или:
х²-12х+20=0
D= b²- 4ac= 144-80=64 D>0,два корня.
х1,х2= - b ± √D/2a= 12± 8/2= 2 ; 10
x²-12x+20= (x -2)(x-10)