4x²+7x+3 = 4(x-0.75)(x+1) = (4x-3)(x+1)
4x²+7x+3 = 0
D = b²-4ac = 49-48 = 1, D>0
x1 = (-b+√D):2a = (-7+1):8 = 0,75
x2 = (-b+√D):2a = (-7-1):8 = -1
4x²+7x+3 = 4(x-0.75)(x+1) = (4x-3)(x+1)
4x²+7x+3 = 0
D = b²-4ac = 49-48 = 1, D>0
x1 = (-b+√D):2a = (-7+1):8 = 0,75
x2 = (-b+√D):2a = (-7-1):8 = -1