Расстояние между пунктами а и в по реке равно 2 км. на путь из а в в и обратно лодка затратила 11/30 часа. какова собственная скорость лодки, если скорость течения реки равна 1 км/ч? обозначив собственную скорость лодки за x км\ч, составьте уравнение
Aruzhka001
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08.06.2019 05:40
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2
2(x-1)+2(x+1) / (x+1)(x-1) =11/30
2x-2+2x+2 / (x-1)(x+1) = 11/30
4x / (x-1)(x+1) = 11/30
120x=11x2 - 11
11x2 - 120x - 11= 0
D=14400 + 484=14844=122 в кв
x1=(120 +122) / 22 =11
x2=(120 - 122) / 22 = не подходит
ответ 11 км/ч
Вроде бы так