Представьте в виде произведения: 1)(а-5)2-16b2 2)x2-y2-5x-5y 3)27-x9

(a-5)²-16b²=(a-5)²-(4b)²=((a-5)+4b)((a-5)-4b)=(a-5+4b)(a-5-4b)

x²-y²-5x-5y=(x²-y²)+(-5x-5y)=(x+y)(x-y)-5(x+y)=(x+y)((x-y)-5)=(x+y)(x-y-5)

27-x⁹=3³-(x³)³=(3-x³)(3²+3x³+(x³)²)=(3-x³)(9+3x³+x⁶)