Очень жизненно небходимо решить квадратные уравнения : 1) 5x²-9x-2=0
2)2x²-11x+5=0
3)5x²+11x+2=0
4)3x²-7x+2=0
5)2x²-3x-2=0

Aksiomsa868589 Aksiomsa868589    3   27.03.2021 14:30    0

Ответы
VarmaleyYouTuber VarmaleyYouTuber  26.04.2021 14:30

1) \: \: \:5 x {}^{2} - 9x - 2 = 0 \\ d = ( - 9) {}^{2} - 4 \times 5 \times ( - 2) = 81 + 40 = 121 \\ x1 = \frac{9 + 11}{2 \times 5} = \frac{20}{10} = 2 \\ x2 = \frac{9 - 11}{2 \times 5} = - \frac{2}{10} = - \frac{1}{5}

2) \: \: \: \: \: 2x {}^{2} - 11x + 5 = 0 \\ d = ( - 11) {}^{2} - 4 \times 2 \times 5 = 121 - 40 = 81 \\ x1 = \frac{11 + 9}{2 \times 2} = \frac{20}{4} = 5 \\ x2 = \frac{11 - 9}{2 \times 2} = \frac{2}{4} = \frac{1}{2}

Объяснение:

3) \: \: \: 5x {}^{2} + 11x + 2 =0 \\ d = 11 {}^{2} - 4 \times 5 \times 2 = 121 - 40 = 81 \\ x1 = \frac{ - 11 + 9}{2 \times 5} = - \frac{2}{10 } = - \frac{1}{5} \\ x2 = \frac{ - 11 - 9}{2 \times 5} = - \frac{20}{10} = - 2

4) \: \: \: \: 3x {}^{2} - 7x + 2 = 0 \\ d = ( - 7) {}^{2} - 4 \times 3 \times 2 = 49 - 24 = 25 \\ x1 = \frac{7 + 5}{2 \times 3} = \frac{12}{6} = 2 \\ x2 = \frac{7 - 5}{2 \times 3} = \frac{2}{6} = \frac{1}{3}

5) \: \: \: \: 2x {}^{2} - 3x - 2 = 0 \\ d = ( - 3) {}^{2} - 4 \times 2 \times ( - 2) = 9 + 16 = 25 \\ x1 = \frac{3 + 5}{2 \times 2} = \frac{8}{4} = 2 \\ x2 = \frac{3 - 5}{2 \times 2} = - \frac{2}{4} = - \frac{1}{2}

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Юлиана95631 Юлиана95631  26.04.2021 14:30

1)5х2−9−2=0,  =5,  =−9,  =−2.

D=b²-4ac=81+40=121=11²

x_{1} =\frac{-b-\sqrt{D} }{2a} =\frac{9-11}{2*5} =\frac{-2}{10} =-0.2\\

x_{2}=\frac{-b+\sqrt{D} }{2a} =\frac{9+11}{10} =\frac{20}{10} =2

2)2x²-11x+5=0    a=2,  b=-11,   c=5

D=b²-4ac=121-40=81=9²

x_{1} =\frac{-b-\sqrt{D} }{2a} =\frac{11-9}{4} =\frac{2}{4}=\frac{1}{2} =0.5\\x_{2} =\frac{-b+\sqrt{D} }{2a} =\frac{11+9}{4} =\frac{20}{4} =5

3)5x²+11x+2=0

D=121-40=81=9²

x_{1} =\frac{-11-9}{10} =\frac{-20}{10} =-2\\x_{2} =\frac{-11+9}{10} =\frac{-2}{10} =-0.5

4)3x²-7x+2=0

D=49-24=25=5²

x_{1} =\frac{7-5}{6} =\frac{2}{6} =\frac{1}{3} \\x_{2} =\frac{7+5}{6} =\frac{12}{6} =2

5)2x²-3x-2=0

D=9+16=25=5²

x_{1} =\frac{3-5}{4}=\frac{2}{4} =-\frac{1}{2} =-0.5\\x_{2} =\frac{3+5}{4} =\frac{8}{4} =2

Удачи!
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