-√2/2
Объяснение:
y=cosx x₀= π/4
k=?
k=y`(x₀)
y`(x)=(cosx)`= -sinx
y`(x₀) = y`(π/4) = -sin(π/4) = -√2/2
k= -√2/2
-√2/2
Объяснение:
y=cosx x₀= π/4
k=?
k=y`(x₀)
y`(x)=(cosx)`= -sinx
y`(x₀) = y`(π/4) = -sin(π/4) = -√2/2
k= -√2/2