Объяснение:
y=x+(9/x) [(1/2;4]
y'=(x+(9/x))'=1+(9*x⁻¹)'=1-9*x⁻²=1-(9/x²)=0.
9/x²=1
x²=9
x₁=-3 ∉ [(1/2);4] x₂=3 ∈[(1/2);4] ⇒
y(1/2)=(1/2)+9/(1/2)=0,5+18=18,5=унаиб.
y(3)=3+(9/3)=3+3=6=yнаим.
y(4)=4+(9/4)=6,25.
Объяснение:
y=x+(9/x) [(1/2;4]
y'=(x+(9/x))'=1+(9*x⁻¹)'=1-9*x⁻²=1-(9/x²)=0.
9/x²=1
x²=9
x₁=-3 ∉ [(1/2);4] x₂=3 ∈[(1/2);4] ⇒
y(1/2)=(1/2)+9/(1/2)=0,5+18=18,5=унаиб.
y(3)=3+(9/3)=3+3=6=yнаим.
y(4)=4+(9/4)=6,25.