Найдите корни уравнения 6x(2x+1)=5x+1

6Х * ( 2X + 1 ) = 5X + 1 
12X^2 + 6X - 5X - 1 = 0 
12X^2 + X - 1 = 0

D = 1 + 48 = 49 ; √ D = 7
X1 = ( - 1 + 7 ) : 24 = 6/24 = 1/4 = 0,25
X2 = ( - 1 - 7 ) : 24 = ( - 8/24 ) = ( - 1/3 )