Найдите корни уравнения : 5 x ² + 12 x + 7 = 0​

(x+1)(5x+7)

(x+1)(5x+7) view step

(x+1)(5x+7) view stepx+1=05x+7=0

(x+1)(5x+7) view stepx+1=05x+7=0x=-1

(x+1)(5x+7) view stepx+1=05x+7=0x=-1x=−1

(x+1)(5x+7) view stepx+1=05x+7=0x=-1x=−1x=-\frac{7}{5}

5 x ² + 12 x + 7 = 0

а=5; b=12; c=7

D=b²-4ac=12²-4×5×7=144-140=4

x1= 7/5

x2=-1