Методом подстановки. x2-3y=1 x-2y=1

X2-3y=1
x=1+2y

(1+2y)2-3y=1
1+4y+4y2-3y-1=0
4y2+y=0
y(4y+1)=0
y=0  y=-1/4
x=1  x=1/2

Х^2-3y=1
x=1+2y

(1+2y)^2-3y=1
x=1+2y

1+4y+4y^2-3y=1
x=1+2y

4y^2+y=0
x=1+2y

y(4y+1)=0
x=1+2y

y1=0
4y+1=0
x=1+2y

y1=0
4y=-1
x=1+2y

y1=0
y2= -(1/4)
x1=1+2*0
x2=1+2*(-1/4)

y1=0
y2= -(1/4)
x1=1
x2=1-1/2

y1=0
y2= -(1/4)
x1=1
x2=1/2=0,5