(log3 2+log2 81 +4)(log3 2-2log18 2)log2 3-log3 2 подробно

1)log(3)2+log(2)81+4=log(3)2+4/log(3)2+4=
=(log²(3)2+4log(3)2+4)/log(3)2=(log(3)2+2)²/log(3)2
2)log(3)2-2log(18)2=log(3)2-2log(3)2/(log(3)2+2)=
=(log²(3)2+2log(3)2-2log(3)2)/(2+log(3)2)=log²(3)2/(log(3)2+2)
3)(log²(3)2+2)²/log(3)2 * log²(3)2/(log(3)2+2)*1/log(3)2=
=log(3)2+2
4)log(3)2+2-log(3)2=2