Log₅(9-2)+log₅125=5 решите уравнение,

Log₅(9-2)+log₅125=5 <=> Log₅7+3=5 <=> Log₅7=2 - это не верно ))

Если же Log₅(9-x)+log₅125=5 <=> Log₅(9-x)+3=5 <=> Log₅(9-x)=2 <=> Log₅(9-x)=2*Log₅5 <=> Log₅(9-x)=Log₅25 <=> 9-x=25 <=> x=-16.