log(a^k) b^l = l/k * log(a) b
log(7) 3 = a
log(7) 5 = b
log(7) 25 - log(7) 243 = log(7) 5² - log(7) 3⁵ = 2 log(7) 5 - 5 log(7) 3 = 2b - 5a
log(a^k) b^l = l/k * log(a) b
log(7) 3 = a
log(7) 5 = b
log(7) 25 - log(7) 243 = log(7) 5² - log(7) 3⁵ = 2 log(7) 5 - 5 log(7) 3 = 2b - 5a