Для функции f(x)=3x-0.2x(в квадрате) найдите: 1)f(-15) 2)f(0.2) 3)f(2/3)

F(x)=3x-0.2x² = x(3-0.2x)
1) f(-15)= -15(3-0.2*15)= -15(3-3)=0
2) f(0.2)= 0.2(3-0.2*0.2)=0.2*2.96=0.592
3) f(2/3)=2/3 (3-0.2*(2/3))=2/3 (3 - (1/5)*(2/3))=
    =2/3 (3 - 2/15) =2/3 * (43/15) =86/45 = 1 ⁴¹/₄₅