(b^3-b^2)(b^3+b^2)-(1+b^2)(1-b^2+b^4) b=0,1

Question

Алгебра: (b^3-b^2)(b^3+b^2)-(1+b^2)(1-b^2+b^4) b=0,1

Xomka03 · Answer

-1,0001Объяснение:(b^3-b^2)(b^3+b^2)-(1+b^2)(1-b^2+b^4) = (b^3)^2 - (b^2)^2 - (1^3 + (b^2)^3) = b^6 - b^4 - 1 - b^6 = - b^4 - 1.Если b=0,1, то- 0,1^4 - 1 = - 0,0001 - 1 = -1,0001....

(b^3-b^2)(b^3+b^2)-(1+b^2)(1-b^2+b^4) b=0,1

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(b^3-b^2)(b^3+b^2)-(1+b^2)(1-b^2+b^4)
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