A=log(98)56. выразите log(7) 14 через а

A=log(98)56=log(7)56/log(7)98=(3log(7)2+1)/(log(7)2+2)
Alog(7)2+2A=3log(7)2+1
log(7)2*(A-3)=1-2A
log(7)2=(1-2A)/(A-3)
log(7)14=1+log(7)2=1+(1-2A)/(A-3)=(A-3+1-3A)/(A-3)=(-2-2A)/(a-3)=
=(2+2A)/(3-A)