А) arctg1-arctg√3=π/4-π/3=(3π-4π)/12=-π/12; б) arcsin √2/2+arccos 1/2=π/4+π/3=7π/12;
в)arccos(-√3/2)+arcsin(-√3/2)=5π/6+(-π/3)=(5π-2π)/6=3π/6=π/2;
г)-arctg(-√3)+arctg 1/√3=-(-π/3)+π/6=(2π+π)/6=3π/6=π/2.
№ 5Сравните: а)arcsin⁡((-√2)/2)и arccos⁡((-√2)/2); -π/4 -π/4 ; arcsin(-1/2)>arctg(-1);
в) arccos((-√3)/2) и 1+arctg√3; 5π/6> 1+π/3; arccos((-√3)/2)> 1+arctg√3;
г) arcctg(-√3) и arctg(-√3) ; 5π/6>-π/3; arcctg(-√3)>arctg(-√3) ;

Chillin    1   24.11.2020 12:38    0