А)3х+8х-3=0 б)х2+6х+4=0 решите через дискременат

а)3х^2+8х-3=0

D = b^2 - 4ac = 8^2 - 4*3*(-3) = 64 - (-36) = 64 + 36 = 100

VD = V100 = 10

                -b (+)(-) VD

X1/2 =

                        2a

x1 = (-8+10)/2*3 = 2/6 = 1/3

x2 = (-8-10)/2*3 = -18/6 = -3

б)х^2+6х+4=0

D = b^2 - 4ac = 6^2 - 4*1*4 = 36 - 16 = 20

VD = V20 = V(4*5) = 2V5

                -b (+)(-) VD

X1/2 =

                        2a

               -6 + 2V5

x1 =

                     2

                -6 - 2V5

x2 =

                    2

 а)

D=16+9=25
x=(-4+-5)/3
x1=-3  x2=1/3.

б)

D=9-4=5
x1=-3+sqrt(5)
x2=-3-sqrt(5).