336/527
Объяснение:
sinα=-√1-(7/25)²=-√1-49/625=-√(625-49)/625=-√576/625=-24/25
sin2a =2·(-24/25)·7/25=-336/625
cos2a=(7/25)²-(-24/25)²=49/625-576/625=-527/625,
tg2a=sin2a/cos2a=-336/625:(-527/625)=336/527
336/527
Объяснение:
sinα=-√1-(7/25)²=-√1-49/625=-√(625-49)/625=-√576/625=-24/25
sin2a =2·(-24/25)·7/25=-336/625
cos2a=(7/25)²-(-24/25)²=49/625-576/625=-527/625,
tg2a=sin2a/cos2a=-336/625:(-527/625)=336/527