2х + 5у - у в квадрате=6 2 х+у=11 решите функцию

kilala00 kilala00    1   10.03.2019 15:31    1

Ответы
Anhelodek Anhelodek  24.05.2020 17:22

 

     2х=11-у                                                                        yy-4y-5=0
={                                                                                       y1+y2=4
    11-y +5y-yy=6                                                               y1*y2=-5
    2x=11-y                                                                          y1+y2=5-1
={                                                                                         y1*y2=5*(-1)
    yy-4y-5=0
     x=(11-5)|2
={    
     y=5
     x=3                                x=6
={                      или              
      y=5                                y=-1

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