1) (x+y) ^2 = (x+y) (x+y) = 2) (5a+1) ^2=
3) (m-3) ^3=
4) (1-b) ^2=
5) (x-1) (1|x + 1) =
6) (a|b - 1) (a+b) =
7) (y+1|y) (y-1|y) =
8) (x-1|y) (x+1|y) =
9) (2k-1) (k+2) =
10) (3b-4) (4b-3) =
11) (5n+1) (4n-3) =
12) (9c+5) (7c+2) =
13) (a+1) (a+2) =a•a+a•2+1•a+1•2=
14) (x-2) (x+3) =
15) (y+1) (y-4) =
16) (m-5) (m-2) =

Piachenka150    3   23.02.2021 14:48    0