а)
ответ:
б)
а) sin(133°)cos(73°)−cos(133°)sin(73°)=sin(133°-73°)=sin60°=(√3)/2
б) cos(π/14)cos(19π/28)−sin(π/14)sin(19π/28)=cos((π/14)+(19π28))=cos(21π/28)=
=cos(3π/4)=-√2/2
а)
ответ:
б)
ответ:
а) sin(133°)cos(73°)−cos(133°)sin(73°)=sin(133°-73°)=sin60°=(√3)/2
б) cos(π/14)cos(19π/28)−sin(π/14)sin(19π/28)=cos((π/14)+(19π28))=cos(21π/28)=
=cos(3π/4)=-√2/2