1) 5 – 3(2х + 7) = 4(2 – х);

2) 3х(х – 1) – 17 = х(1 + 3х) + 1;

3) 2х – (х + 2)(2 – х) = 5 – (х – 1)2;

Question

Алгебра: 1) 5 – 3(2х + 7) = 4(2 – х); 2) 3х(х – 1) – 17 = х(1 + 3х) + 1; 3) 2х – (х + 2)(2 – х) = 5 – (х – 1)2;

hvbdnnd · Answer

1)5-3(2х+7)=4(2-х)5-6х-21=8-4х-16-6х=8-4х-16-8=-4х+6х-24=2хх= -24:2х= -122)3х(х-1)-17=х(1+3х)+13х²-3х-17=х+3х²+13х²-3х-х-3х²=1+17-4х=18х= -(18:4)х=4,53)2х-(х+2)(2-х)=5-(х-1)22х-х-2(2-х)=5-2х+22х-х-4+2х=5-2х+23х-4=7-2х3х+2х=7+45х=11х=11:5х=2,2...

1) 5 – 3(2х + 7) = 4(2 – х); 2) 3х(х – 1) – 17 = х(1 + 3х) + 1; 3) 2х – (х + 2)(2 – х) = 5 – (х – 1)2;

Популярные вопросы

1) 5 – 3(2х + 7) = 4(2 – х);

2) 3х(х – 1) – 17 = х(1 + 3х) + 1;

3) 2х – (х + 2)(2 – х) = 5 – (х – 1)2;