1).(1/3)^3 / 3^2*(1/3)^3 = 2).3a*4b^2-0,8b*4b^2-2ab*3b+b*3b^2-1 = 3).(7,3y-y^2+4)+0,5y^2-(8,7y-2,4y^2) = 4).1-(0,5x-15,8)=12,8-0,7x =

Gromokon    2   02.08.2020 00:38    0